Advertisements
Advertisements
प्रश्न
Find the equation of the following circles having the centre (0,0) and radius 2 units
उत्तर
Equation of the circle when centre origin (0, 0) and radius r is x2 + y2 = r2
⇒ x2 + y2 = 22
⇒ x2 + y2 = 4
⇒ x2 + y2 – 4 = 0
APPEARS IN
संबंधित प्रश्न
Find the centre and radius of the circle
x2 + y2 – 22x – 4y + 25 = 0
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
Find the values of a and b if the equation (a - 1)x2 + by2 + (b - 8)xy + 4x + 4y - 1 = 0 represents a circle.
If the circle touches the x-axis, y-axis, and the line x = 6 then the length of the diameter of the circle is:
Obtain the equation of the circles with radius 5 cm and touching x-axis at the origin in general form
Find the equation of circles that touch both the axes and pass through (− 4, −2) in general form
Find the equation of the circles with centre (2, 3) and passing through the intersection of the lines 3x – 2y – 1 = 0 and 4x + y – 27 = 0
If y = `2sqrt(2)x + "c"` is a tangent to the circle x2 + y2 = 16, find the value of c
If the equation 3x2 + (3 – p)xy + qy2 – 2px = 8pq represents a circle, find p and q. Also determine the centre and radius of the circle
Choose the correct alternative:
The equation of the normal to the circle x2 + y2 – 2x – 2y + 1 = 0 which is parallel to the line 2x + 4y = 3 is
