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Find the general solutions of the following equation : sinθ = tanθ - Mathematics and Statistics

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प्रश्न

Find the general solution of the following equation:

sin θ = tan θ.

योग

उत्तर

sin θ = tan θ
∴ sinθ = `"sinθ"/"cosθ"`
∴ sinθ cosθ = sinθ
∴ sinθ cosθ – sinθ = 0
∴ sinθ (cosθ – 1) = 0
∴ either sinθ = 0 or cosθ – 1 = 0
∴ either sinθ = 0 or cosθ = 1
∴ either sinθ = 0 or cosθ = cos0  ...[∵ cos 0 = 1]

The general solution of sin θ = 0 is θ = nπ, n ∈ Z and  cosθ = cos α is θ = 2nπ ± α, where n ∈ Z.

∴ the required general solution is given by
θ = nπ, n ∈ Z or θ = 2nπ ± 0, n ∈ Z
∴ θ = nπ, n ∈ Z or θ = 2nπ, n ∈ Z.

shaalaa.com
Trigonometric Equations and Their Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 3 Trigonometric Functions
Exercise 3.1 | Q 7.1 | पृष्ठ ७५

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