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Find the general solutions of the following equation: tanθ=-3 - Mathematics and Statistics

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प्रश्न

Find the general solutions of the following equation:

`tan theta = - sqrt3`

योग

उत्तर

The general solution of tan θ = tan α is

θ = nπ + α, n ∈ Z.

Now, tan θ = - `sqrt3`

∴ tan θ = - `tan  pi/3    ....[because "tan" pi/3 = sqrt3]`

∴ tan θ = tan`(pi - pi/3)   ...[because tan (pi - theta) = - tan theta]`

∴ tan θ = tan`(2pi)/3`

∴ the required general solution is

∴ θ = `"n"pi + (2pi)/3,` n ∈ Z

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Trigonometric Equations and Their Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 4.1 | पृष्ठ १०९

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