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Find the greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36? - Mathematics

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प्रश्न

Find the greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36?

योग

उत्तर

To find L.C.M. of 24, 15, 36


24 = 23 × 3

15 = 3 × 5

36 = 22 × 32 

Prime factors of
24, 15, 36
Greatest
Exponents
2 3
3 2
5 1

∴ L.C.M. = 23 × 32 × 51

= 8 × 9 × 5

= 360

If a number has to be exactly divisible by 24, 15, and 36, then it has to be divisible by 360. Greatest 6 digit number is 999999.

Common multiplies of 24, 15, 36 with 6 digits are 103680, 116640, 115520, …, 933120, 999720 with six digits.

∴ The greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36 is 999720.

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अध्याय 2: Numbers and Sequences - Exercise 2.2 [पृष्ठ ४६]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 2 Numbers and Sequences
Exercise 2.2 | Q 7 | पृष्ठ ४६
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