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प्रश्न
Find the mean of 53, 61, 60, 67 and 64.
उत्तर
Mean of 53, 61, 60, 67 and 64
∴ Mean =`(53+61+60+67+64)/5` .....(Here n = 5)
= `305/5`
= 61
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संबंधित प्रश्न
Calculate the mean of the following distribution using step deviation method.
| Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| Number of students |
10 | 9 | 25 | 0 | 16 | 10 |
Find the mode and the median of the following frequency distribution:
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
1) Using step–deviation method, calculate the mean marks of the following distribution.
2) State the modal class.
| Class Interval | 50 - 55 | 55 - 60 | 60 - 65 | 65 - 70 | 70 - 75 | 75 - 80 | 80 - 85 | 85 – 90 |
| Frequency | 5 | 20 | 10 | 10 | 9 | 6 | 12 | 8 |
The mean of the following distribution is 52 and the frequency of class interval 30-40 is ‘f’. Find ‘f’.
| Class Interval | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency | 5 | 3 | f | 7 | 2 | 6 | 13 |
The mean of the following distribution is 62.8 and the sum of all the frequencies is 50. Find the missing frequencies f1 and f2.
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 | 100 – 120 |
| Frequency | 5 | f1 | 10 | f2 | 7 | 8 |
The following table shows the expenditure of 60 boys on books. Find the mode of their expenditure:
| Expenditure (Rs) | No. of students |
| 20 – 25 | 4 |
| 25 – 30 | 7 |
| 30 – 35 | 23 |
| 35 – 40 | 18 |
| 40 – 45 | 6 |
| 45 – 50 | 2 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
| Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| Frequency | 4 | 12 | 21 | 18 | 15 | 7 | 3 |
Find the mean of all factors of 10.
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is, multiplied by 2
The median of first ten even natural numbers is ___________
