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प्रश्न
Find the mode and the median of the following frequency distribution:
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
उत्तर
x | f | cf |
10 | 1 | 1 |
11 | 4 | 5 |
12 | 7 | 12 |
13 | 5 | 17 |
14 | 9 | 26 |
15 | 3 | 29 |
N = 29 |
Here `N = 29 => N/2 = 29/2 = 14.5`
We find that the cf just greater than `N/2 = 14.5` is 17 and the value of x corresponding to 17 is 13.
Therefore, Median = 13
To find mode: From the table, it is clear that the value 14 has maximum frequency 9.
Hence, the mode of the data is 14.
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