Advertisements
Advertisements
प्रश्न
Find the median of the following sets of numbers.
15, 8, 14, 20, 13, 12, 16
उत्तर
15, 8, 14, 20, 13, 12, 16
Arranging the data in ascending order,
8, 12, 13, 14, 15, 16, 20
Here N = 7
∴ Median is `(("N" + 1)/2)^"th"` term
= `((7 + 1)/2)` = 4th term
∴ Median = 14.
APPEARS IN
संबंधित प्रश्न
The following table shows the expenditure of 60 boys on books. Find the mode of their expenditure:
Expenditure (Rs) | No. of students |
20 – 25 | 4 |
25 – 30 | 7 |
30 – 35 | 23 |
35 – 40 | 18 |
40 – 45 | 6 |
45 – 50 | 2 |
Find the mean, median and mode of the following marks obtained by 16 students in a class test marked out of 10 marks:
0, 0, 2, 2, 3, 3, 3, 4, 5, 5, 5, 5, 6, 6, 7 and 8.
The marks obtained by 120 students in a mathematics test is given below:
Marks | No. of students |
0 – 10 | 5 |
10 – 20 | 9 |
20 – 30 | 16 |
30 – 40 | 22 |
40 – 50 | 26 |
50 – 60 | 18 |
60 – 70 | 11 |
70 – 80 | 6 |
80 – 90 | 4 |
90 – 100 | 3 |
Draw an ogive for the given distributions on a graph sheet. Use a suitable scale for your ogive. Use your ogive to estimate:
- the median
- the number of student who obtained more than 75% in test.
- the number of students who did not pass in the test if the pass percentage was 40.
- the lower quartile.
Find the mean of first 10 prime numbers.
Find the mean of the following frequency distribution :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
Frequency | 4 | 4 | 7 | 10 | 12 | 8 | 5 |
Find the mean of the following frequency distribution :
Class | 101-110 | 111-120 | 121-130 | 131-140 | 141-150 | 151-160 |
Frequency | 11 | 16 | 20 | 30 | 14 | 9 |
Find the mode of the following:
20, 20, 30, 30, 30, 30, 35, 40, 40, 45, 45, 45, 50, 55, 60, 60, 60 ,65, 70, 70, 70
The mean of six numbers: x − 5, x − 1, x, x + 2, x + 4 and x + 12 is 15. Find the mean of first four numbers.
Find the mean of the first six multiples of 5.
The heights (in cm) of 8 girls of a class are 140, 142, 135, 133, 137, 150, 148 and 138 respectively. Find the mean height of these girls and their median height.