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Question
Find the median of the following sets of numbers.
15, 8, 14, 20, 13, 12, 16
Solution
15, 8, 14, 20, 13, 12, 16
Arranging the data in ascending order,
8, 12, 13, 14, 15, 16, 20
Here N = 7
∴ Median is `(("N" + 1)/2)^"th"` term
= `((7 + 1)/2)` = 4th term
∴ Median = 14.
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RELATED QUESTIONS
From the data given below, calculate the mean wage, correct to the nearest rupee.
| Category | A | B | C | D | E | F |
| Wages (Rs/day) | 50 | 60 | 70 | 80 | 90 | 100 |
| No. of workers | 2 | 4 | 8 | 12 | 10 | 6 |
- If the number of workers in each category is doubled, what would be the new mean wage?
- If the wages per day in each category are increased by 60%; what is the new mean wage?
- If the number of workers in each category is doubled and the wages per day per worker are reduced by 40%, what would be the new mean wage?
The following table gives the weekly wages of workers in a factory.
| Weekly wages (Rs) | No. of workers |
| 50 – 55 | 5 |
| 55 – 60 | 20 |
| 60 – 65 | 10 |
| 65 – 70 | 10 |
| 70 – 75 | 9 |
| 75 – 80 | 6 |
| 80 – 85 | 12 |
| 85 – 90 | 8 |
Calculate the mean by using:
Direct Method
Find the mean of the following frequency distribution :
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| Frequency | 4 | 4 | 7 | 10 | 12 | 8 | 5 |
The weights of 11 students in a class are 36 kg, 45 kg, 44 kg, 37 kg, 36 kg, 41 kg, 45 kg, 43 kg, 39 kg, 42 kg and 40 kg. Find the median of their weights.
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Find the median of the 10 observations 36, 33, 45, 28, 39, 45, 54, 23, 56, 25. If another observation 35 is added to the above data, what would be the new median?
An incomplete frequency distribution is given below
| Variate | Frequency |
| 10 – 20 | 12 |
| 20 – 30 | 30 |
| 30 – 40 | ? |
| 40 – 50 | 65 |
| 50 – 60 | 45 |
| 60 – 70 | 25 |
| 70 – 80 | 18 |
| Total | 229 |
Median value is 46, the missing frequency is:
