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प्रश्न
Find the modal and median classes of the following distribution.
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency | 11 | 22 | 19 | 18 | 7 |
उत्तर
| Class | Frequency | cf |
| 0 – 20 | 11 | 11 |
| 20 – 40 | 22 | 33 |
| 40 – 60 | 19 | 52 |
| 60 – 80 | 13 | 65 |
| 80 – 100 | 7 | 72 |
| `sumf_i` = 72 |
Here, highest frequency is 22
Hence, modal class is 20 – 40
Also, N = `sumf_i` = 72
Now, `N/2 = 72/2` = 36
36 lies in cumulative frequency 52
So, median class is 40 – 60.
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संबंधित प्रश्न
Calculate the median from the following data:
| Marks below: | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
| No. of students: | 15 | 35 | 60 | 84 | 96 | 127 | 198 | 250 |
An incomplete distribution is given below:
| Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |
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(i) Using the median formula fill up missing frequencies.
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| Class | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 | 40 – 45 |
| Frequency | 5 | 6 | 15 | 10 | 5 | 4 | 2 | 2 |
In the graphical representation of a frequency distribution, if the distance between mode and mean is ktimes the distance between median and mean, then write the value of k.
If the median of the data: 24, 25, 26, x + 2, x + 3, 30, 31, 34 is 27.5, then x =
If the mean of the following distribution is 3, find the value of p.
| x | 1 | 2 | 3 | 5 | p + 4 |
| f | 9 | 6 | 9 | 3 | 6 |
Find the median of:
66, 98, 54, 92, 87, 63, 72.
Find the median of the scores 7, 10, 5, 8, 9.
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Weekly income of 600 families is tabulated below:
| Weekly income (in Rs) |
Number of families |
| 0 – 1000 | 250 |
| 1000 – 2000 | 190 |
| 2000 – 3000 | 100 |
| 3000 – 4000 | 40 |
| 4000 – 5000 | 15 |
| 5000 – 6000 | 5 |
| Total | 600 |
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