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Find the slope of the tangent to the following curves at the respective given points. y = x4 + 2x2 – x at x = 1 - Mathematics

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प्रश्न

Find the slope of the tangent to the following curves at the respective given points.

y = x4 + 2x2 – x at x = 1

योग

उत्तर

y = x4 + 2x2 – x

Differentiating w.r.t. ‘x’

`"d"y)/("d"x = 4x3 + 4x – 1

Slope of the tangent `(("d"y)/("d"x))_((x = 1))`

= 4(1)³ + 4(1) – 1

= 4 + 4 – 1

= 7

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Meaning of Derivatives
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अध्याय 7: Applications of Differential Calculus - Exercise 7.2 [पृष्ठ १४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 7 Applications of Differential Calculus
Exercise 7.2 | Q 1. (i) | पृष्ठ १४

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