Advertisements
Advertisements
प्रश्न
Find the sum and product of the roots for the following quadratic equation
3y2 – y – 4 = 0
उत्तर
3y2 – y – 4 = 0 ÷ 3
`y^2 - y/3 - 4/3` = 0
`y^2 - (1/3)y + ((-4)/3)` = 0
∴ α + β = `(1)/(3)`
αβ = `(-4)/(3)`
APPEARS IN
संबंधित प्रश्न
Determine the quadratic equation, whose sum and product of roots are – (2 – a)2, (a + 5)2
Find the sum and product of the roots for the following quadratic equation
x2 + 3x = 0
Solve the following quadratic equation by factorization method
4x2 – 7x – 2 = 0
Solve the following quadratic equation by factorization method
3(p2 – 6) = p(p + 5)
Solve the following quadratic equation by completing the square method
9x2 – 12x + 4 = 0
Solve the following quadratic equation by formula method
36y2 – 12ay + (a2 – b2) = 0
If the difference between a number and its reciprocal is `24/5`, find the number
The roots of the equation 2x2 – 7x + 5 = 0 are α and β. Without solving for the roots, find `alpha/beta + beta/alpha`
The roots of the equation x2 + 6x – 4 = 0 are α, β. Find the quadratic equation whose roots are α2 and β2
`x/(x^2 - 25) - 8/(x^2 + 6x + 5)` gives
