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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Solve the following quadratic equation by factorization method 3(p2 – 6) = p(p + 5) - Mathematics

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प्रश्न

Solve the following quadratic equation by factorization method

3(p2 – 6) = p(p + 5)

योग

उत्तर

3p2 – 18 = p2 + 5p

2p2 – 5p – 18 = 0

2p2 – 9p + 4p – 18 = 0

p(2p – 9) + 2(2p – 9) = 0

(2p – 9)(p + 2) = 0

2p – 9 = 0 or p + 2 = 0

The roots are p = `(9)/(2), -2`

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Quadratic Equations
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अध्याय 3: Algebra - Exercise 3.10 [पृष्ठ १११]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.10 | Q 1. (ii) | पृष्ठ १११
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