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Find the sum of G.P. : 1 + 3 + 9 + 27 + .......... to 12 terms. - Mathematics

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प्रश्न

Find the sum of G.P. :

1 + 3 + 9 + 27 + .......... to 12 terms. 

योग

उत्तर

Given G.P. : 1 + 3 + 9 + 27 + ..........

Here,

First term, a = 1

Common ratio, r =`3/1` = 3  ...(∵ r > 1)

Number of terms to be added, n = 12

∴ `S_n = (a(r^n - 1))/(r - 1)`

`=> S_12 = (1(3^12 - 1))/(3 - 1)`

= `(3^12 - 1)/2`

= `(531441 - 1)/2`

= `531440/2`

= 265720

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Simple Applications - Geometric Progression
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Geometric Progression - Exercise 11 (D) [पृष्ठ १६१]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 11 Geometric Progression
Exercise 11 (D) | Q 1.1 | पृष्ठ १६१
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