हिंदी

Find the sum to n terms 0.4 + 0.44 + 0.444 + ... - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find the sum to n terms 0.4 + 0.44 + 0.444 + ...

योग

उत्तर

Sn = 0.4 + 0.44 + 0.444 + … upto n terms

= 4(0.1 + 0.11 + 0.111 + …. upto n terms)

= `4/9` (0.9 + 0.99 + 0.999 + ... upto n terms)

= `4/9` [(1 − 0.1) + (1 − 0.01) + (1 − 0.001) ... upto n terms]

= `4/9` [(1 + 1 + 1 ... n times) − (0.1 + 0.01 + 0.001 + ... upto n terms)]

But 0.1, 0.01, 0.001, … n terms are in G.P.

with a = 0.1, r = `0.01/0.1` = 0.1

∴ Sn = `4/9{"n" - 0.1[(1 - (0.1)^"n")/(1 - 0.1)]}`

∴ Sn = `4/9 {"n" - 0.1/0.9 [1 - (0.1)^"n"]}`

∴ Sn = `4/9 ["n" - 1/9 (1 - (0.1)^"n")]`

∴ Sn = `4/81 {9"n" - (1 - 1/10^"n")}`

shaalaa.com
Arithmetico Geometric Series
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Sequences and Series - Exercise 2.2 [पृष्ठ ३१]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 2 Sequences and Series
Exercise 2.2 | Q 6. (i) | पृष्ठ ३१

संबंधित प्रश्न

Find the sum to n terms 8 + 88 + 888 + 8888 + ...


Find Sn of the following arithmetico - geometric sequence: 

2, 4x, 6x2, 8x3, 10x4, …


Find Sn of the following arithmetico - geometric sequence:

1, 2 × 3, 3 × 9, 4 × 27, 5 × 81, …


Find the sum to infinity of the following arithmetico - geometric sequence:

`1, 2/4, 3/16, 4/64, ...`


Find the sum to infinity of the following arithmetico - geometric sequence:

`3, 6/5, 9/25, 12/125, 15/625, ...`


Find the sum to infinity of the following arithmetico - geometric sequence:

`1, -4/3, 7/9, -10/27 ...`


Find the sum `sum_("r" = 1)^"n" ("r" + 1)(2"r" - 1)`


Find `sum_("r" = 1)^"n"(3"r"^2 - 2"r" + 1)`


Find `sum_("r" = 1)^"n"((1 + 2 + 3  .... +  "r")/"r")`


Find `sum_("r" = 1)^"n" [(1^3 + 2^3 + .... +  "r"^3)/("r"("r" + 1))]`


Find the sum 22 + 42 + 62 + 82 + ... upto n terms


Find (702 – 692) + (682 – 672) + (662 – 652) + ... + (22 – 12)


Answer the following:

Find 2 + 22 + 222 + 2222 + ... upto n terms


Answer the following:

Find `sum_("r" = 1)^"n" "r"("r" - 3)("r" - 2)`


Answer the following:

Find `sum_("r" = 1)^"n" ((1^3 + 2^3 + 3^3 + ... "r"^3)/("r" + 1)^2)`


Answer the following:

Find 2 × 6 + 4 × 9 + 6 × 12 + ... upto n terms


Answer the following:

Find 2 × 5 × 8 + 4 × 7 × 10 + 6 × 9 × 12 + ... upto n terms


Answer the following:

Find `1^2/1 + (1^2 + 2^2)/2 + (1^2 + 2^2 + 3^2)/3 + ...` upto n terms


Answer the following:

Find (502 – 492) + (482 – 472) + (462 – 452) + ... + (22 – 12)


Answer the following:

If  `(1 xx 3 + 2 xx 5 + 3 xx 7 + ...  "upto n terms")/(1^3 + 2^3 + 3^3 + ...  "upto n terms") = 5/9`, find the value of n


Answer the following:

If p, q, r are in G.P. and `"p"^(1/x) = "q"^(1/y) = "r"^(1/z)`, verify whether x, y, z are in A.P. or G.P. or neither.


The sum of n terms of the series 22 + 42 + 62 + ........ is ______.


`(x + 1/x)^2 + (x^2 + 1/x^2)^2 + (x^3 + 1/x^3)^2` ....upto n terms is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×