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प्रश्न
Find the value of x° in the following figure:
योग
उत्तर
Join OP
∠QPR = `80/2` = 40° ...(Angle of the circumference is `1/2` the angle at the centre)
∠RPO = 30° ...(OP and OR are equal sides)
∠OPQ = 40° – 30°
= 10°
∠OQP = 10° ...(OQ and OP are equal sides)
∴ x = 10°
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Angle at the Centre and the Circumference
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Geometry - Exercise 4.3 [पृष्ठ १७०]
