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प्रश्न
Find the value of x° in the following figure:
योग
उत्तर
∠OAC + ∠OCA = 180° – 100°
= 80°
∠OAC = `1/2 xx 80^circ` ...[Since OA = OC, (∴ ∠OAC = ∠OCA)]
= 40°
∠OBA + ∠OAB = 180° – 140°
= 40° ...[Since ∠OBA = ∠OAB, since OB = OA]
∴ ∠OAB = `(40^circ)/2`
= 20°
∠BAC = ∠OAB + ∠OAC
= 20° + 40°
x = 60°
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Angle at the Centre and the Circumference
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