Advertisements
Advertisements
प्रश्न
Find the value of x° in the following figure:
बेरीज
उत्तर
∠OAC + ∠OCA = 180° – 100°
= 80°
∠OAC = `1/2 xx 80^circ` ...[Since OA = OC, (∴ ∠OAC = ∠OCA)]
= 40°
∠OBA + ∠OAB = 180° – 140°
= 40° ...[Since ∠OBA = ∠OAB, since OB = OA]
∴ ∠OAB = `(40^circ)/2`
= 20°
∠BAC = ∠OAB + ∠OAC
= 20° + 40°
x = 60°
shaalaa.com
Angle at the Centre and the Circumference
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
