Question

Find the values of the following trigonometric ratio:

\[\sin\frac{17\pi}{6}\]

 

Answer 1

We have: 
\[\sin\frac{17\pi}{6} = \sin 510^\circ\]
\[510^\circ = \left( 90^\circ \times 5 + 60 \right)^\circ\]
\[510^\circ\text{ lies in the second quadrant in which the sine function is positive . }\]
Also, 5 is an odd integer . 
\[ \therefore \sin\left( 510^\circ \right) = \sin \left( 90^\circ \times 5 + 60^\circ \right) = \cos \left( 60^\circ \right) = \frac{1}{2}\]