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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ९

For what value of k is the polynomial p(x) = 2x3 – kx2 + 3x + 10 exactly divisible by (x – 2) - Mathematics

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प्रश्न

For what value of k is the polynomial p(x) = 2x3 – kx2 + 3x + 10 exactly divisible by (x – 2)

योग

उत्तर

p(x) = 2x3 – kx2 + 3x + 10

When it is exactly divided by x – 2,

p(2) = 0

2(2)3 – k(2)2 + 3(2) + 10 = 0

2(8) – k(4) + 6 + 10 = 0

16 – k(4) + 6 + 10 = 0

16 – 4k + 6 + 10 = 0

32 – 4k = 0

32 = 4k

∴ k = `32/4`

= 8

The value of k = 8

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अध्याय 3: Algebra - Exercise 3.3 [पृष्ठ ९६]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 3 Algebra
Exercise 3.3 | Q 5 | पृष्ठ ९६
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