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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

For what value of k is the polynomial p(x) = 2x3 – kx2 + 3x + 10 exactly divisible by (x – 2) - Mathematics

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Question

For what value of k is the polynomial p(x) = 2x3 – kx2 + 3x + 10 exactly divisible by (x – 2)

Sum

Solution

p(x) = 2x3 – kx2 + 3x + 10

When it is exactly divided by x – 2,

p(2) = 0

2(2)3 – k(2)2 + 3(2) + 10 = 0

2(8) – k(4) + 6 + 10 = 0

16 – k(4) + 6 + 10 = 0

16 – 4k + 6 + 10 = 0

32 – 4k = 0

32 = 4k

∴ k = `32/4`

= 8

The value of k = 8

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Chapter 3: Algebra - Exercise 3.3 [Page 96]

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Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 3 Algebra
Exercise 3.3 | Q 5 | Page 96
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