Advertisements
Advertisements
प्रश्न
From the sum of 4 + 3x and 5 - 4x + 2x2, subtract the sum of 3x2 - 5x and -x2 + 2x + 5.
उत्तर
(4 + 3x) + (5 - 4x + 2x2) = 4 + 3x + 5 - 4x + 2x2
= 3x - 4x + 2x2 + 4 + 5
= -x + 2x2 + 9
(3x2 - 5x) + (- x2 + 2x + 5) = 3x2 - 5x - x2 + 2x + 5
= 3x2 - x2 - 5x + 2x + 5
= 2x2 - 3x + 5
(-x + 2x2 + 9) - (2x2 - 3x + 5)
= -x + 2x2 + 9 - 2x2 + 3x - 5
= -x + 3x + 2x2 - 2x2 + 9 - 5
= 2x + 4
APPEARS IN
संबंधित प्रश्न
Add the following:
ab − bc, bc − ca, ca − ab
Add: -7mn + 5, 12mn + 2, 9mn - 8, -2mn - 3
Subtract: (a - b) from (a + b)
Subtract: 4pq - 5q2 - 3p2 from 5p2 + 3q2 - pq
Subtract:
− 5xy from 12xy
If \[x + \frac{1}{x} = 9,\] find the value of \[x^4 + \frac{1}{x^4} .\]
Add:
−3y2 + 10y − 16; 7y2 + 8
Simplify: n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
The sum of –7pq and 2pq is ______.
Sum of x2 + x and y + y2 is 2x2 + 2y2.