Advertisements
Advertisements
प्रश्न
From the velocity – time graph given below, calculate Distance covered in the region ABCE.
उत्तर
Distance covered in region ABCE = ar(ΔABF) + area of trapezium BCEF
= `1/2xx"AF"xx"BF"+1/2("BF+CF")xx"GC"`
= `1/2xx12xx14+1/2(14+6)xx4`
= 6 × 14 + 10 × 4
= 84 + 40
= 124 m
APPEARS IN
संबंधित प्रश्न
Fill in the following blank with suitable word :
In a speed-time graph, the area enclosed by the speed-time curve and the time axis gives the…………….. by the body.
A body is moving uniformly in a straight line with a velocity of 5 m/s. Find graphically the distance covered by it in 5 seconds.
Multiple choice Question. Select the correct option.
The slope of displacement – time graph represents.
Multiple choice Question. Select the correct option.
What does the area of an acceleration – time graph represent?
Multiple choice Question. Select the correct option.
In the velocity-time graph, the acceleration is
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform acceleration.
What can you conclude if the speed-time graph of a body is a straight line sloping upwards and not passing through the origin?
Draw distance-time graph to show:
Decreasing velocity
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
How far did B travel between the time he passed C and A?
Mention the uses of the velocity-time graph.
