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प्रश्न
Give reason for the following:
When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
उत्तर
Sulphur dioxide gets oxidized when exposed to air to form sulphur trioxide which reacts with water vapours to form sulphuric acid.
\[\ce{SO2 + H2O + O2 -> 2H2SO4}\]
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संबंधित प्रश्न
State one relevant observation for given reactions:
Addition of ethyl alcohol to acetic acid in the presence of concentrated Sulphuric acid
How will you distinguish between dilute hydrochloric acid and dilute sulphuric acid using lead nitrate solution?
A, B, C, and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.
A = Typical acid property
B = Non volatile acid
C = Oxidizing agent
D = Dehydrating agent
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2) Preparation of Copper sulphate from copper oxide.
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What would you see, when a crystal of CuSO4.5H2O is placed in concentrated sulphuric acid? Give reason to explain your observation.
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Give one equation to show the following properties of sulphuric acid:
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Write balanced chemical equation to show :
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Name the gas released when sodium carbonate is added to a solution of sulphur dioxide.