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प्रश्न
Give reason for the following:
When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
उत्तर
Sulphur dioxide gets oxidized when exposed to air to form sulphur trioxide which reacts with water vapours to form sulphuric acid.
\[\ce{SO2 + H2O + O2 -> 2H2SO4}\]
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संबंधित प्रश्न
Give balanced chemical equations for the action of sulphuric acid on the following:
Potassium hydrogen carbonate.
Give one equation to show the following properties of sulphuric acid:
As a non-volatile acid
Give two balanced reactions of the type to show the following property of sulphuric acid:
Acidic nature.
Name the products formed when hot and concentrated sulphuric acid reacts with Copper.
Name the Following:
The property used to prepare HCl and HNO3 from H2SO4.
Give reason for the following:
When carbon is heated with concentrated sulphuric acid, carbon dioxide is formed.
The following statement is correct only under certain conditions. Rewrite the statement including the appropriate conditions.
Oxalic acid reacts with sulphuric acid to produce carbon monoxide and carbon dioxide.
Name the gas released when sodium carbonate is added to a solution of sulphur dioxide.
Name the anion present in the following compound:
Compound D, when warmed with dilute sulphuric acid, gives a gas that turns acidified dichromate solution green.
A, B and C are the chemical properties of sulphuric acid:
A. Oxidizing agent
B. Dehydrating agent
C. Non-volatile acid
Match the following equations 1 to 3 to the above chemical properties of sulphuric acid.
1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
2. \[\ce{C12H22O11 -> 12C + 11H2O}\]
3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\]
