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प्रश्न
Give reasons On the basis of E° values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl.
उत्तर
The anode is positive in the electrolytic cell and oxidation takes place. Therefore, at anode H2O, OH-, Cl- gets attracted (negative charge gets attracted to positive charge) but OH- cannot oxidise because hydrogen is in maximum oxidation state and to oxidise H20, we need more electricity (overpotential) because of presence of hydrogen bond so, Cl- gets oxidised to produce Cl2 gas
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संबंधित प्रश्न
The conductivity of 0.20 M solution of \[\ce{KCl}\] at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.
The resistance of a conductivity cell containing 0.001M \[\ce{ KCl}\] solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M \[\ce{KCl}\] solution at 298 K is 0.146 × 10−3 S cm−1.
Define conductivity for the solution of an electrolyte.
The cell constant of a conductivity cell ______.
ConductivityK, is equal to:
(i) `1/R l/A`
(ii) `G^∗/R`
(iii) Λm
(iv) `l/A`
In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Assertion: Conductivity of all electrolytes decreases on dilution.
Reason: On dilution number of ions per unit volume decreases.
The unit of equivalent conductivity is
The cell constant is the product of resistance and ______
The decreasing order of electrical conductivity of the following aqueous solutions is:
- 0.1 M Formic acid,
- 0.1 M Acetic acid,
- 0.1 M Benzoic acid.
