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प्रश्न
Give reasons On the basis of E° values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl.
उत्तर
The anode is positive in the electrolytic cell and oxidation takes place. Therefore, at anode H2O, OH-, Cl- gets attracted (negative charge gets attracted to positive charge) but OH- cannot oxidise because hydrogen is in maximum oxidation state and to oxidise H20, we need more electricity (overpotential) because of presence of hydrogen bond so, Cl- gets oxidised to produce Cl2 gas
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संबंधित प्रश्न
The conductivity of 0.20 M solution of \[\ce{KCl}\] at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.
The resistance of a conductivity cell containing 0.001M \[\ce{ KCl}\] solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M \[\ce{KCl}\] solution at 298 K is 0.146 × 10−3 S cm−1.
Define conductivity for the solution of an electrolyte.
When measuring conductivity with a conductivity cell, cell constant denoted by the symbol G* is given by (electrode area of cross-section equal to ‘A’ and separated by distance ‘l’)
The cell constant of a conductivity cell ______.
Conductivity of an electrolytic solution depends on:
(i) nature of electrolyte.
(ii) concentration of electrolyte.
(iii) power of AC source.
(iv) distance between the electrodes.
ConductivityK, is equal to:
(i) `1/R l/A`
(ii) `G^∗/R`
(iii) Λm
(iv) `l/A`
In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Assertion: Conductivity of all electrolytes decreases on dilution.
Reason: On dilution number of ions per unit volume decreases.
Which of the following is not the characteristic of ionic solids?
