Advertisements
Advertisements
प्रश्न
ConductivityK, is equal to:
(i) `1/R l/A`
(ii) `G^∗/R`
(iii) Λm
(iv) `l/A`
उत्तर
(i) `1/R l/A`
(ii) `G^∗/R`
Explanation:
`K = 1/R ∗ 1/A` or `G^∗/R`
APPEARS IN
संबंधित प्रश्न
The conductivity of 0.20 M solution of \[\ce{KCl}\] at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.
The resistance of a conductivity cell containing 0.001M \[\ce{ KCl}\] solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M \[\ce{KCl}\] solution at 298 K is 0.146 × 10−3 S cm−1.
Give reasons On the basis of E° values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl.
In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Assertion: Conductivity of all electrolytes decreases on dilution.
Reason: On dilution number of ions per unit volume decreases.
Assertion: For measuring resistance of an ionic solution an AC source is used.
Reason: Concentration of ionic solution will change if DC source is used.
The unit of equivalent conductivity is
Which of the following is not the characteristic of ionic solids?
The conductivity of 0.01 m NaCl solution is 0.00147 ohm–1cm–1. What happens to the conductivity if extra 100 ML is added to the above solution:-
The cell constant is the product of resistance and ______
