हिंदी

How can you find the following? Acceleration from velocity – time graph. - Physics

Advertisements
Advertisements

प्रश्न

How can you find the following?

Acceleration from velocity – time graph.

आलेख

उत्तर

Acceleration from velocity – time graph: Velocity – time graph for uniform motion in a straight line (OP) inclined to the time axis.

Take any two points A and B on this graph. From A and B draw perpendicular on the time axis as well as velocity axis in such a way that

OA1 = t1, OB1 = t2, OA2 = v1 and OB2 = v2

Slope of v – t graph = `"BC"/"AC"`

= `("v"_2-"v"_1)/("t"_2-"t"_1)=(Δ"v")/(Δ"t")` = Acceleration of the body

So, by knowing the slope of velocity – time graph for uniform motion, we can find the acceleration of the body.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Motion in One Dimension - Unit II Exercise 2 (B) Subjective Questions

APPEARS IN

गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
अध्याय 2 Motion in One Dimension
Unit II Exercise 2 (B) Subjective Questions | Q 3.2

संबंधित प्रश्न

Fill in the following blank with a suitable word:

Acceleration is the rate of change of ______ It is measured in ______


Find the initial velocity of a car which is stopped in 10 seconds by applying brakes. The retardation due to brakes is 2.5 m/s2.


Describe the motion of a body which is accelerating at a constant rate of 10 m s2. If the body starts from rest, how much distance will it cover in 2 s ?


A cheetah starts from, rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :
(a) the final velocity
(b) the distance travelled.


Give one example of following motion :

Variable acceleration


Derive the following equations for uniformly accelerated motion: 

(i) v = u + at 

(ii) `"S = ut" + 1/2 "at"^2`

(iii) v2 = u2 + 2aS

where the symbols have their usual meanings.


Multiple choice Question. Select the correct option.

At the maximum height, a body thrown vertically upwards has :


A girl walks along a straight path to drop a letter in the letterbox and comes back to her initial position. Her displacement–time graph is shown in Fig.8.4. Plot a velocity-time graph for the same.


The velocity-time graph (Fig. 8.5) shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity and (iii) the distance covered by the cyclist in 15 seconds.


An electron moving with a velocity of 5 × 104 ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms–2 in the direction of its initial motion.

(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.

(ii) How much distance the electron would cover at this time?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×