हिंदी

Derive the Following Equations for Uniformly Accelerated Motion: (I) V = U + at (Ii) S = Ut + 1 2 at 2 (Iii) V2 = U2 + 2as Where the Symbols Have Their Usual Meanings. - Physics

Advertisements
Advertisements

प्रश्न

Derive the following equations for uniformly accelerated motion: 

(i) v = u + at 

(ii) `"S = ut" + 1/2 "at"^2`

(iii) v2 = u2 + 2aS

where the symbols have their usual meanings.

संक्षेप में उत्तर

उत्तर

Derivation of equations of motion

First equation of motion: 

Consider a particle moving along a straight line with uniform acceleration 'a'. At t = 0, let the particle be at A and u be its initial velocity, and at t = t, let v be its final velocity.

Acceleration = Change in velocity/Time a = (v - u)/t at = v - u

v = u+ at ... First equation of motion.

Second equation of motion: Average velocity = Total distance traveled/Total time taken Average velocity = s/t ...(1)

Average velocity can be written as (u+v)/2 Average velocity = (u+v)/2 ...(2)

From equations (1) and (2) s/t = (u+v)/2 ...(3)

The first equation of motion is v = u + at.

Substituting the value of v in equation (3), we get

s/t = (u + u + at)/2 s = (2u + at) t/2 = 2ut + at2/2 = 2ut/2 + at2/2

s = ut + (1/2) at2 …Second equation of motion.

Third equation of motion: The first equation of motion is v = u + at. v - u = at ... (1)

Average velocity = s/t ...(2)

Average velocity =(u+v)/2 ...(3)

From equation (2) and equation (3) we get,

(u + v)/2 = s/t ...(4)

Multiplying eq (1) and eq (4) we get,

(v - u)(v + u) = at × (2s/t) (v - u)(v + u) = 2as

[We make the use of the identity a2 - b2 = (a + b) (a - b)]

v2 - u2 = 2as ...Third equation of motion.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Motion in One Dimension - Exercise 2 (C) [पृष्ठ ५४]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 2 Motion in One Dimension
Exercise 2 (C) | Q 2 | पृष्ठ ५४
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×