Question

How many moles of ethane is required to produce 44 g of \[\ce{CO2_{(g)}}\] after combustion.

Answer 1

Balanced equation for the combustion of ethane

\[\ce{C2H6 + 7/2O2 -> 2CO2 + 3H2O}\]

\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]

To produce 4 moles of CO₂, 2 moles of ethane is required

∴ To produce 1 mole (44 g) of CO₂ required

Number of moles of ethane = `(2  "mol ethane")/(4  "mol CO"_2) xx 1  "mol CO"_2`

= `1/2` mole of ethane

= 0.5 mole of ethane