Advertisements
Advertisements
प्रश्न
How many numbers lie between 10 and 300, which when divided by 4 leave a remainder 3?
उत्तर
Number between 10 and 300, which when divided by 4 leave a remainder 3 will be 11, 15, 19, 23,...299
Here, a = 11, d = 15 – 11 = 4, l = 299
∴ Tn = l = a + (n – 1)d
299 = 11 + (n –1) x 4
⇒ 299 – 11 = (n – 1)4
4(n – 1) = 288
⇒ n – 1 = `(288)/(4)` = 72
∴ n = 72 + 1
= 73.
APPEARS IN
संबंधित प्रश्न
Split 207 into three parts such that these parts are in A.P. and the product of the two smaller parts in 4623.
Insert four A.M.s between 14 and -1.
For an A.P., show that (m + n)th term + (m – n)th term = 2 × mthterm
If the first term of an A.P. is – 18 and its 10th term is zero, then find its common difference.
Which term of the A.P. 7, 13, 19, … is 205?
Determine the A.P. whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20.
If the seventh term of an A.P. is `(1)/(9)` and its ninth term is `(1)/(7)`, find its 63rd term.
Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5.
If the numbers n – 2, 4n – 1 and 5n + 2 are in A.P., find the value of n.
The sum of the first three terms of an A.P.is 33. If the product of the first and the third terms exceeds the second term by 29, find the A.P.