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प्रश्न
How much is y4 – 12y2 + y + 14 greater than 17y3 + 34y2 – 51y + 68?
उत्तर
Required expression is y4 – 12y2 + y + 14 – (17y3 + 34y2 – 51y + 68) = y4 – 12y2 + y + 14 – 17y3 – 34y2 + 51y – 68
On combining the like terms,
= y4 – 12y2 – 34y2 + y + 51y + 14 – 68 – 17y3
= y4 – 46y2 + 52y – 17y3 – 54
= y4 – 17y3 – 46y2 + 52y – 54
So, y4 – 12y2 + y + 14 is y4 – 17y3 – 46y2 + 52y – 54 greater than 17y3 + 34y2 – 51y + 68.
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