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प्रश्न
How will the action of dilute hydrochloric acid enable you to distinguish between sodium carbonate and sodium sulphite?
उत्तर
Sodium carbonate treated with \[\ce{dil. HCl}\] results in the formation of sodium chloride with the liberation of carbon dioxide gas.
\[\ce{Na2CO3 + 2HCl ⟶ 2NaCl + H2O + CO2 ↑}\]
Sodium sulphite treated with \[\ce{dil. HCl}\] results in the formation of sodium chloride with the liberation of sulphur dioxide gas.
\[\ce{Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 ↑}\]
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संबंधित प्रश्न
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| Column A | Column B |
| 1. A substance that turns moist starch iodide paper blue. | A. Ammonium sulphate |
| 2. A compound which release a reddish brown gas on reaction with concentrated sulphuric acid and copper turnings. | B. Lead carbonate |
| 3. A solution of this compound gives dirty green precipitate with sodium hydroxide. | C. Chlorine |
| 4. A compound which on heating with sodium hydroxide produces a gas which forms dense white fumes with hydrogen chloride. | D. Copper nitrate |
| 5. A white solid which gives a yellow residue on heating | E. Ferrous sulphate |
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