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How will the action of dilute hydrochloric acid enable you to distinguish between sodium carbonate and sodium sulphite? - Chemistry

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Question

How will the action of dilute hydrochloric acid enable you to distinguish between sodium carbonate and sodium sulphite?

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Solution

Sodium carbonate treated with \[\ce{dil. HCl}\] results in the formation of sodium chloride with the liberation of carbon dioxide gas.

\[\ce{Na2CO3 + 2HCl ⟶ 2NaCl + H2O + CO2 ↑}\]

Sodium sulphite treated with \[\ce{dil. HCl}\] results in the formation of sodium chloride with the liberation of sulphur dioxide gas.

\[\ce{Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 ↑}\]

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General Preparation of Hydrogen Chloride Gas
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Chapter 8: Study of Compounds - Hydrogen Chloride - Exercise 8 [Page 148]

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Selina Concise Chemistry [English] Class 10 ICSE
Chapter 8 Study of Compounds - Hydrogen Chloride
Exercise 8 | Q 10. (a) | Page 148
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