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प्रश्न
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with sodium sulphite.
उत्तर
Gas Evolved:
When dilute hydrochloric acid reacts with sodium sulphite, the gas evolved is sulphur dioxide.
Reaction:
\[\ce{Na2SO3 + 2HCl -> 2NaCl + H2O + SO2 ^}\]
Chemical Test for sulphur dioxide: Pass the gas through an acidified potassium dichromate \[\ce{(K2Cr2O7}\]) solution.
Observation: The solution changes color from orange to green due to the reduction of chromium from \[\ce{Cr^{6+}}\] to \[\ce{Cr^{3+}}\].
\[\ce{SO2 + H2O + K2Cr2O7 + H2SO4 -> Cr2(SO4)3 + K2SO4 + H2O}\]
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संबंधित प्रश्न
Identify the acid in each case:
The acid which produces sugar charcoal from sugar
Name the products formed when hot and concentrated sulphuric acid reacts with Sugar.
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(i) Potassium nitrate
(ii) carbon
Give balanced chemical equation for the action of sulphuric acid of the following:
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Write the balanced chemical equation for the following conversion:
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State two observations when
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Hydrogen chloride gas is prepared in the laboratory by the action of concentrated sulphuric acid on sodium chloride.
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