Advertisements
Advertisements
प्रश्न
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
योग
उत्तर
3a + 2b − 6c + 4d
= 3 × 3 + 2 × 0 − 6 × 2 + 4 × 1
= 9 + 0 − 12 + 4
= 9 + 0 − (12 − 4)
= 9 − 8
= 1
shaalaa.com
Concept of Substitution
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the value of 4pq × 2r, when p = 5, q = 3 and r = 1/2
Find the value of 5x2 – 3x + 2, when x = 2.
State true and false:
The value of 2x – 3 = 1, when x = 0
Evaluate:
6m – (4m – m)
Simplify:
a − (a − b − c)
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Simplify:
x − [y + {x − (y + x)}]
Insert the bracket as indicated:
m2 + x2 − p2 = − (...................)
If x = 3, y = 2 and z = 1; find the value of y2 – x2 + 6z2
Simplify:
6 {3x – 8 (5x – 10)}
