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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

If ∆ABC ~ ∆DEF such that area of ∆ABC is 9 cm2 and the area of ∆DEF is 16 cm2 and BC = 2.1 cm. Find the length of EF. - Mathematics

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प्रश्न

If ∆ABC ~ ∆DEF such that area of ∆ABC is 9 cm2 and the area of ∆DEF is 16 cm2 and BC = 2.1 cm. Find the length of EF.

योग

उत्तर

Given ∆ABC ~ ∆DEF

∴ `("Area of"  Delta"ABC")/("Area of"  Delta"DEF") = "BC"^2/"EF"^2`  ...(Square of their corresponding sides)

`9/16 = (2.1)^2/"EF"^2`

`(3/4)^2 = (2.1/"EF")^2`

`3/4 = 2.1/"EF"`

EF = `(4 xx 2.1)/3` = 2.8 cm

Length of EF = 2.8 cm

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Geometry - Exercise 4.1 [पृष्ठ १७१]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 4 Geometry
Exercise 4.1 | Q 8 | पृष्ठ १७१
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