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If ЁЭЫ╝, ЁЭЫ╜ are the zeroes of the polynomial `f(x) = 5x^2 -7x + 1` then `1/∝+1/β=?`
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By using the relationship between the zeroes of he quadratic polynomial. We have
Sum of zeroes=`(-("Coefficient of x"))/("Coefficient of "x^2)`Sum of zeroes = `"Constant term"/("Coefficient of" x^2) `
∴` ∝+β=-(-7)/5 and ∝β=1/5`
⇒` ∝+β =7/5 and ∝β=1/5`
Now,`1/∝+1/β= (∝+β)/(∝β)`
=`(7/5)/(1/5)`
= 7
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