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If the Heights of Two Right Circular Cones Are in the Ratio 1 : 2 and the Perimeters of Their Bases Are in the Ratio 3 : 4, What is the Ratio of Their Volumes? - Mathematics

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प्रश्न

If the heights of two right circular cones are in the ratio 1 : 2 and the perimeters of their bases are in the ratio 3 : 4, what is the ratio of their volumes?

संक्षेप में उत्तर

उत्तर

Given that,

`h_1:h_2 = 1 : 2 " and " 2pir_1 :2pir_2 = 3 :4`

`i.e., r_1 :r_2 = 3:4`

Therefore,

The ratios of volume of their cones will be

`v_1 : v _2 = 1/3pi r_1^2 h_1 :1/3 pir_2^2 h_2`

    `V_1/V_2 = (1/3 pir_1^2 h_1)/(1/3 pir_1^2 h_2)`

          `=(r_1/r_2)^1 xx (h_1 /h_2)`

        `V_1/V_2 = (3/4)^2 xx (1/2)`

              `=9/32`

    `V_1 :V_2 = 9: 32`

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अध्याय 14: Surface Areas and Volumes - Exercise 14.4 [पृष्ठ ८६]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.4 | Q 2 | पृष्ठ ८६

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