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If the distance of the point (1, 1, 1) from the plane x -y + z + λ = 0 is 53, find the value(s) of λ. - Mathematics

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प्रश्न

If the distance of the point (1, 1, 1) from the plane x – y + z + λ = 0 is `5/sqrt(3)`, find the value(s) of λ.

योग

उत्तर

We know that, distance of (x1, y1, z1) from a plane ax + by + cz + d = 0 is given by p = `|(ax_1 + by_1 + cz_1 + d)/sqrt(a^2 + b^2 + c^2)|`

Given, p = `5/sqrt(3)` and (x1, y1, z1) = (1, 1, 1)

∴ `5/sqrt(3) = |(1 - 1 + 1 + λ)/sqrt(1^2 + 1^2 + 1^2)|`

⇒ `5/sqrt(3) = |(λ + 1)/sqrt(3)|`

⇒ λ + 1 = ±5

⇒ λ = 4 or –6

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2021-2022 (April) Term 2 - Outside Delhi Set 1

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