Advertisements
Advertisements
प्रश्न
If the roots of the quadratic equation x2 + 12x + a = 0 are real and equal, then find the value of a.
उत्तर
Equation given is, x2 + 12x + a = 0
As a result of the quadratic equation's real and equal roots,
∴ Discriminant, D = 0
⇒ B2 – 4AC = 0
⇒ (12)2 – 4 × 1 × a = 0
⇒ 4a = 144
⇒ a = 36
As a result, a has a value of 36.
APPEARS IN
संबंधित प्रश्न
If the roots of 2x2 - 6x + k = 0 are real and equal, find k.
If α and β are the roots of the quadratice equation x²- 2x - 7= 0, find the
value α² + β²
If α and β are the roots of the quadratic equation `x^2 - 4x - 6 = 0`, find the values of (i) `α^2+β^2` (ii) `α^3+β^3`
Form the quadratic equation if the roots are 3 and 8.
Form the quadratic equation if its roots are 5 and 7.
Solve the quadratic equation : 3x4 - 13x2 +10 = 0.
Convert the following equations into simultaneous equations and solve:
`sqrt("x"/"y") = 4, 1/"x" + 1/"y" = 1/"xy"`
Choose the correct alternative answer for the following sub-questions and write the correct alphabet.
Which of the following quadratic equation has roots – 3 and – 5?
Write the roots of following quadratic equation.
(p – 5) (p + 3) = 0
Solve the following quadratic equation.
`sqrt(3) x^2 + sqrt(2)x - 2sqrt(3)` = 0
Solve the following quadratic equations by formula method.
`y^2 + 1/3y` = 2
Solve the following quadratic equation.
`1/(4 - "p") - 1/(2 + "p") = 1/4`
One of the roots of equation kx2 – 10x + 3 = 0 is 3. Complete the following activity to find the value of k.
Activity:
One of the roots of equation kx2 – 10x + 3 = 0 is 3.
Putting x = `square` in the above equation
∴ `"k"(square)^2 - 10 xx square + 3` = 0
∴ `square` – 30 + 3 = 0
∴ 9k = `square`
∴ k = `square`
If the sum of the roots of the quadratic equation x2 + kx + 6 = 0 is 6, then the value of k is ______.
The value of the discriminant of the equation x2 + 6x – 15 = 0 is ______.
If x = `sqrt(7) - 2`, find the value of `(x + 1/x)`.
One of the roots of equation x2 + 5x + a = 0 is – 3. To find the value of a, fill in the boxes.
Since, `square` is a root of equation x2 + 5x + a = 0
∴ Put x = `square` in the equation
⇒ `square^2 + 5 xx square + a` = 0
⇒ `square + square + a` = 0
⇒ `square + a` = 0
⇒ a = `square`
Find the roots of the quadratic equation `x^2 - (sqrt(3) + 1)x + sqrt(3)` = 0.