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प्रश्न
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
5 + 2x = `9: 3(1)/(2)y + 1` = 12 - 3y
उत्तर
For abscissa,
5 + 2x = 9 ....(given)
2x = 9 - 5
x = `(4)/(2)`
∴ x = 2
For ordinate,
`3(1)/(2)y+ 1` = 12 - 3y ....(given)
`(7)/(2)y + 3y` = 12 - 1
`((7 + 6)y)/(2)` = 11
13y = 22
∴ y = `(22)/(13)`
∴ The coordinates of the point are `(2, 22/13)`.
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संबंधित प्रश्न
State, true or false:
The ordinate of a point is its x-co-ordinate.
State, true or false:
The origin (0, 0) lies on the x-axis.
State, true or false:
The point (a, b) lies on the y-axis if b = 0.
In the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
3 - 2x = 7; 2y + 1 = 10 - 2`(1)/(2)`y.
In the following, find the co-ordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
`5x - (5 - x) = (1)/(2) (3 - x); 4 -3y = (4 + y)/(3)`
Plot point A(5, -7). From point A, draw AM perpendicular to the x-axis and AN perpendicular to the y-axis. Write the coordinates of points M and N.
Find the co-ordinates of points whose: Abscissa is 5 and ordinate is -1
Find the co-ordinates of points whose: Abscissa is 0 and ordinate is 0
Find the co-ordinates of points whose: Abscissa is -7 and ordinate is 4
___________ coordinates are the same for a line parallel to Y-axis