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प्रश्न
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
(7 - x) + 7x = `(x + 5); (2 + 3y)/(2)` = 2y - 6
उत्तर
For abscissa,
(7 - x) + 7x = (x + 5) ....(given)
7 - x + 7x = x + 5
6x - x = 5 - 7
5x = -2
∴ x = `-(2)/(5)`
For ordinate,
`(2 + 3y)/(2)` = 2y - 6 ....(given)
2 + 3y = 2(2y - 6)
2 + 3y = 4y - 12
3y - 4y = -12 - 2
-y = -14
∴ y = 14
∴ The coordinates of the point are `(-2/5, 14)`.
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