Advertisements
Advertisements
प्रश्न
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
(7 - x) + 7x = `(x + 5); (2 + 3y)/(2)` = 2y - 6
उत्तर
For abscissa,
(7 - x) + 7x = (x + 5) ....(given)
7 - x + 7x = x + 5
6x - x = 5 - 7
5x = -2
∴ x = `-(2)/(5)`
For ordinate,
`(2 + 3y)/(2)` = 2y - 6 ....(given)
2 + 3y = 2(2y - 6)
2 + 3y = 4y - 12
3y - 4y = -12 - 2
-y = -14
∴ y = 14
∴ The coordinates of the point are `(-2/5, 14)`.
APPEARS IN
संबंधित प्रश्न
Find the values of x and y if:
(5x - 3y, y - 3x) = (4, -4)
State, true or false:
The ordinate of a point is its x-co-ordinate.
State, true or false:
The y-axis is the vertical number line.
State, true or false:
The origin (0, 0) lies on the x-axis.
Plot point A(5, -7). From point A, draw AM perpendicular to the x-axis and AN perpendicular to the y-axis. Write the coordinates of points M and N.
Find the co-ordinates of points whose: Abscissa is 6 and ordinate is 2
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
5 + 2x = `9: 3(1)/(2)y + 1` = 12 - 3y
A rectangle PQRS is drawn on the coordinate axes such that P is the origin, PQ = 6 units and PS = 5 units. Find the coordinates of the vertices P, Q R and S. Also, find the area of the rectangle.
The x-coordinate is always ______ on the y-axis
___________ coordinates are the same for a line parallel to Y-axis
