Advertisements
Advertisements
प्रश्न
Find the values of x and y if:
(5x - 3y, y - 3x) = (4, -4)
उत्तर
Two ordered pairs are equal.
⇒ Therefore their first components are equal and their second components too are separately equal.
(5x - 3y, y - 3x) = (4, -4)
5x - 3y = 4 .......(A) and y - 3x = -4 ......(B)
Now multiplying the equation (B) by 3, we get
3y - 9x = -12......(C)
Now adding both the equations (A) and (C) , we get
(5x - 3y) + (3y - 9x) = (4 + (-12))
-4x = -8
x = 2
Putting the value of x in the equation (B), we get
y - 3x = -4
⇒ y = 3x -4
⇒ y = 3(2) -4
⇒ y = 2
Therefore we get,
x = 2, y = 2
APPEARS IN
संबंधित प्रश्न
Find the values of x and y if:
(x - 1, y + 3) = (4, 4)
State, true or false:
The ordinate of a point is its x-co-ordinate.
In the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
3 - 2x = 7; 2y + 1 = 10 - 2`(1)/(2)`y.
Plot point A(5, -7). From point A, draw AM perpendicular to the x-axis and AN perpendicular to the y-axis. Write the coordinates of points M and N.
Find the co-ordinates of points whose: Abscissa is 6 and ordinate is 2
Find the co-ordinates of points whose: Abscissa is 0 and ordinate is -3
Find the co-ordinates of points whose: Abscissa is 5 and ordinate is -1
Find the co-ordinates of points whose: Abscissa is -2 and ordinate is 0
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
5 + 2x = `9: 3(1)/(2)y + 1` = 12 - 3y
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
(7 - x) + 7x = `(x + 5); (2 + 3y)/(2)` = 2y - 6