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प्रश्न
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
5 + 2x = `9: 3(1)/(2)y + 1` = 12 - 3y
उत्तर
For abscissa,
5 + 2x = 9 ....(given)
2x = 9 - 5
x = `(4)/(2)`
∴ x = 2
For ordinate,
`3(1)/(2)y+ 1` = 12 - 3y ....(given)
`(7)/(2)y + 3y` = 12 - 1
`((7 + 6)y)/(2)` = 11
13y = 22
∴ y = `(22)/(13)`
∴ The coordinates of the point are `(2, 22/13)`.
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