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प्रश्न
In fission of one uranium - 235 nucleus, the loss in mass is 0.2 a.m.u. Calculate the energy released.
उत्तर
Loss in mass = Δm = 0.2 a.m.u.
1 MeV = 1.6 × 10-13J
1 a.m.u. = 1.66 × 10-27 kg
Energy released E = `(Δm xx 1.66 xx 10^-27 xx c^2)/(1.6 xx 10^(-13))`
= `(0.2 xx 1.66 xx 10^-27 xx 3 xx 10^8 xx 3 xx 10^8)/(1.6 xx 10^-13)`
= 186.2 MeV
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संबंधित प्रश्न
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1) Name the isotope of Uranium which is easily fissionable.
2) Give a reason for your answer.
3) Write a nuclear reaction when Uranium 238 emits an alpha particle to form a Thorium (Th) nucleus
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Name the process, fission or fusion which is possible at ordinary temperature.
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What do you understand by the term nucleus?
What do you understand by the term nucleons?
Mark the correct choice as
- Assertion: Control rods are known as 'neutron seeking rods'
- Reason: Control rods are used to perform sustained nuclear fission reaction
Use the analogy to fill in the blank.
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Name the substance used for nuclear fission.
