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प्रश्न
When four hydrogen nuclei combine to form a helium nucleus in the interior of sun, the loss in mass is 0.0265 a.m.u. How much energy is released?
संख्यात्मक
उत्तर
Given that, Δm = 0.0265 a.m.u.
1 a.m.u. = 1.66 × 10-27 kg
E = Δm × 1.66 × 10-27 × C2J
E = `(0.0265 xx 1.66 xx 10^-27 xx (3 xx 10^8)^2)/(1.6 × 10^-13) "MeV"`
E = `265/10^4 xx (166 xx 10^(-27-2) xx 9 xx 10^16)/(1.6 xx 10^-13)`
E = `(265 xx 166 xx 9 xx 10^(-29+16-4))/(16 xx 10^(- 14))`
E = `(2385 xx 83)/8 xx 10^(-13 + 14 - 4)`
E = `(2385 xx 83)/(8 xx 1000)`
E = `197955/(8 xx 1000)`
E = `197.955/8`
E = 24.7 MeV
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