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प्रश्न
In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.
उत्तर
Freundlich adsorption isotherm for adsorption of gases on solids:
xm=Kp1nIt can also be written aslogxm=log K + 1nlog p">
\[\frac{x}{m} = K p^\frac{1}{n} \]
\[\text{It can also be written as}\]
\[\log\frac{x}{m} = \log K + \frac{1}{n}\log p\]
where x is the mass of the adsorbate, m is the mass of the absorbent and p is the pressure of the gas and n is a constant which is greater than 1.
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संबंधित प्रश्न
Describe Freundlich adsorption isotherm.
Answer in one sentence:
Write an equation for Freundlich adsorption isotherm.
Explain graphically Freundlich adsorption isotherm.
The slope and intercept for plot of `log_10 "x"/"m"` against log10P for Freundlich equation are ____________ and ____________ respectively.
Freundlich adsorption isotherm is given by the expression `x/m = kp^(1/n)` which of the following conclusions can be drawn from this expression.
(i) When `1/n` = 0, the adsorption is independent of pressure.
(ii) When `1/n` = 0, the adsorption is directly proportional to pressure.
(iii) When n = 0, `x/m` vs p graph is a line parallel to x-axis.
(iv) When n = 0, plot of `x/m` vs p is a curve.
Langmuir adsorption isotherm works particularly well.
In the freundilch adsorption isotherm, the value of x/m is 0.4 under a pressure of 0.2 at m calculate the value of the interact
Which of the following statement is INCORRECT regarding the adsorption of a gas on the surface of the solid?
The mass of gas adsorbed, x per unit mass of adsorbed, m was measured at various x pressures p. A graph between `log "x"/"m"` and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of `"x"/"m"` at a pressure of 4 atm is ______.
[Given log 3 = 0.4771]
For Freundlich adsorption isotherm, a plot of log (x/m) (Y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10-4 g. (log 3 = 0.4771)
