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प्रश्न
In the adjacent figure ∠BAC = 90° and AD ⊥ BC then
विकल्प
BD.CD = BC2
AB.AC = BC2
BD.CD = AD2
AB.AC = AD2
उत्तर
BD.CD = AD2
Explanation;
Hint:
ΔBAC ∼ ΔBDA
`"AC"/"AD" = "AB"/"BD"` ...(1)
ΔCAB ∼ ΔCDA
`"AC"/"CD" = "AB"/"AD"` ...(2)
From (1) and (2) we get
`"BD"/"AD" = "AD"/"CD"`
AD2 = BD·CD
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